The core premise is that average worker productivity on eclipse day will dip by 1/24th (assuming 20 mins of “eclipse break” on a 8 hour workday).
And that’s BS on several fronts.
For one, many people have taken days off (PTL or similar) or move their break to the eclipse, which is already accounted for in the averaged productivity statistic.
Second, people in positions they can’t just leave (factory workers on an assembly line, cashiers etc.) will often have to skip on the eclipse.
And people who can leave (I’m thinking of white collar desk jobs here), are often spending a similar amount of worktime off-desk on other days, too, for a myriad of only indirectly productive reasons (networking, thinking on a thorny problem over a smoke…).
The formula assumes
that all of the American workforce spends every minute of their 8 hour day actively working on their desk/station/etc.
that every minute they don’t, is “lost”, work-wise.
that all of that workforce is on the job during eclipse time, but will take a paid break during the actual eclipse
I’d still disagree.
The core premise is that average worker productivity on eclipse day will dip by 1/24th (assuming 20 mins of “eclipse break” on a 8 hour workday).
And that’s BS on several fronts.
For one, many people have taken days off (PTL or similar) or move their break to the eclipse, which is already accounted for in the averaged productivity statistic.
Second, people in positions they can’t just leave (factory workers on an assembly line, cashiers etc.) will often have to skip on the eclipse.
And people who can leave (I’m thinking of white collar desk jobs here), are often spending a similar amount of worktime off-desk on other days, too, for a myriad of only indirectly productive reasons (networking, thinking on a thorny problem over a smoke…).
The formula assumes
All of which are questionable at best.