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No, this is true, proof by induction:
(x+y)^2 = x^2 + y^2
For (x,y) = (0,0) :
(x+y)^2 = (0+0)^2 = (0)^2 = 0
x^2 + y^2 = 0^2 + 0^2 = 0 + 0 = 0
Q. E. D.
Thus it should follow that it applies to every other case. (The other cases are left as an exercise for the reader.)
Go home, ChatGPT, you’re drunk.
