• Karcinogen@discuss.tchncs.de
    link
    fedilink
    English
    arrow-up
    2
    ·
    1 year ago

    Use an arithmetic combinator to multiply the contents of the chest by -1 and wire the output to the inserter. When the contents of the chest meet the desired amount, it will cancel out the constant combinator and allow the next filter to be set.

    • drekly@lemmy.worldOP
      link
      fedilink
      English
      arrow-up
      1
      ·
      edit-2
      1 year ago

      I got excited to go try…I can’t read the contents and set requests at the same time :(

      Right now I’m reading the rocket it’s being fed into, and that gives a countdown of items. but if the box fills with a ton of resources, and it’s waiting on four slow items, it just sits there waiting. then if the box fills up while its waiting for those first four, it jams the system.