Sync Ultra is a very reasonable $17 a YEAR. YouTube Premium is reaching that per MONTH. I have sync downloaded and it was the first thing I did. Thanks j for the beautiful app.
EDIT: There are many counterpoints and actually good discussion happening down below. Even if you don’t agree, thanks for showing me a different perspective!
If you want to support Sync, make sure to support the Lemmy Devs and your instance holders as well!
*This post was made early in the day before the update.
Am I the only one who thinks that sync pro for reddit subscribers should have their one time purchase be honored/restored?
Not with the overhaul required. That said, the asking price is too steep.
The devs time in rewriting and testing a whole new backend for Lemmy isn’t free though.
I got Ultra Lifetime when it launched 13 months ago, $35 as I recall. People who didn’t go the “supportive” route paid $19 for that year. This rubs me up the wrong way
Ultra Lifetime is arguable but as I understand it, it’s not that easy because Google Play doesn’t have a way to transfer subscriptions between apps like that.
Pro I don’t think makes sense because it was pretty cheap to begin with. Pro ended up costing me $0.00062/day ($2.50 11 years ago). Kind of makes me feel guilty to be honest.
I agree.
Yeaaaaa I would like that but I don’t see it being possible or feasible, I bought sync dev years ago, don’t mind throwing another few dollars in
:/ had to buy sync twice. Had it for a few years and one day it was like ! hey I’m not working anymore !
A bit frustrating but honestly sync is worth chipping some money towards.
I actually don’t see an option to buy it once at all, I’m not really wanting to pay a subscription lol
Yeah but the one-time purchase now is hardly another few dollars… Its $99 now, which is absurd.
Edit: I see now that there is a $20 version to remove ads. Still would be great if they honored folks who paid for reddit’s syncpro, especially considering that version blocked reddit ads, and this version blocks ads inserted by the app itself.