downpunxx@fedia.io to Lemmy Shitpost@lemmy.world · 14 days agomath checks outfedia.ioimagemessage-square106fedilinkarrow-up11.57Karrow-down112
arrow-up11.56Karrow-down1imagemath checks outfedia.iodownpunxx@fedia.io to Lemmy Shitpost@lemmy.world · 14 days agomessage-square106fedilink
minus-squareegeres@lemmy.worldlinkfedilinkarrow-up15arrow-down1·edit-212 days agoEehrm, acktually, the tweet is wrong 🤓 You can always be getting a result above average in a series of numbers as long as the nth number is significantly greater than the previous ones. For example, f(x) = x^2 would always be above average for every next number
minus-squareSeasoned_Greetings@lemm.eelinkfedilinkarrow-up3·13 days agoI like the idea of an infinitely exponentially growing base of users seeking help from some poor call center
minus-squareb000rg@midwest.sociallinkfedilinkEnglisharrow-up3·13 days agoThis honestly sounds like it could be the basis for a novella
minus-squareMigmog@lemm.eelinkfedilinkarrow-up2·13 days agoIt sounds like something that happens regularly during an update to software with a lot of users.
minus-squarelseif@sopuli.xyzlinkfedilinkarrow-up3·13 days agoif it is considering the average for all of history, then the rate of change would just have to be consistently greater than 0, right ?
Eehrm, acktually, the tweet is wrong 🤓
You can always be getting a result above average in a series of numbers as long as the nth number is significantly greater than the previous ones. For example, f(x) = x^2 would always be above average for every next number
I like the idea of an infinitely exponentially growing base of users seeking help from some poor call center
This honestly sounds like it could be the basis for a novella
It sounds like something that happens regularly during an update to software with a lot of users.
if it is considering the average for all of history, then the rate of change would just have to be consistently greater than 0, right ?
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